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My question is in regards mostly to gear reduction and torque. I have 6ft snowblowert hat I want to mount on the front of my tractor(I'm too cheap not buy one). Easiest way I can think of is to mount it on the loader arms and drive it with a stand alone engine. So how big of a motor do I need and how much does gearing play into it?

For example if I have a motor that is rated a 15hp at 3600rpm, I'll need to gear it down to 540rpm for the snowblower input. I know that when you gear something down you increase its torque output. So what would the power output of a 15hp/3600rpm motor geared down to 540rpm be? Could it then run a 6ft blower? I know a 15hp tractor is way too small for a 6ft blower.
 

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Horsepower is horsepower, gearing has nothing to do with horsepower,
gearing will change the speed,, so greater force is exerted, but, it is applied over a longer time,,

In your case, gearing is ONLY used to produce the correct rotational speed.

You need to use an engine that produces an appropriate amount of horsepower,,
then,, gearing is used to match the speed.

Some blowers (like garden tractor blowers) can be operated at engine speed,,
PTO/three point hitch blowers require gear reduction,,,
 

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So what would the power output of a 15hp/3600rpm motor geared down to 540rpm be? Could it then run a 6ft blower?
As far as that question,,,
the space shuttle weighs 4.4 million pounds when ready for takeoff,,, your 15 HP engine could move the space shuttle,,
you may be dissatisfied with the speed,,, I would imagine the speed would be about a foot per day.

The same with the snow blower,, 15HP might move the snow a foot,,,
do you want to move snow further than a foot?:dunno:
 

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Horsepower is horsepower, gearing has nothing to do with horsepower,
gearing will change the speed,, so greater force is exerted, but, it is applied over a longer time,,
++++++

Power (horse or otherwise) is basically the product of rotational speed and torque. The math looks complicated when we use lbs-ft and horsepower as units, but that is basically what it is. If you reduce the rotational speed by a factor of four, you increase the torque by a factor of four (ignoring losses in the gear reducer). Multiply the two and you still end up with the same power output.

Al
 

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Just for ball park numbers here, Deere lists 30HP as the minimum requirement for the SB1174 (6') blower. 16HP is their minimum recommendation for the SB1154 (4.5') blower.
 

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It can be done.





Not sure what size that engine is though.


Sent from my iPhone using Tapatalk Pro
 

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There’s a few self powered snow blowers available. Berco makes snow blowers for avts and utv. I have considered buying one of those for the place up north. They use a 23 hp engine. Maybe take a look at one of them for ideas. If my tractor didn’t have mid pto I’d put a blower on my loader.
 

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Discussion Starter #10
Thanks. I did have a look at Bermac and see they are using either a 23 or 25hp engine for their 72" blowers. The price tag was similar to what I would expect to pay for a front mount blower and all the attachments for my tractor. The Bermac has the advantage of being able to easily move it to a different machine...
 
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